How do I use if/then/else or guards in a case statement in Haskell?

The "Guards vs. If-Then-Else" helped a little but I still want to know if this can work somehow. I need to take a list and return every other element of the list. For even length lists I got it just if length (xs) mod 2 == 1 to start is there an issue so I want to break up the initial length of list case like this:

everyOther:: [Int] -> [Int] 
everyOther [] = [] 
everyOther (x:xs) = case length (xs) 'mod' 2 of 0 ->  
if (length (xs) `mod` 2 == 0)   
then  x:everyOther (take 1 xs) 
else x:everyOther (drop 1 xs) 
1 -> if (length (xs) `mod` 2 == 1) 
then  x:everyOther (take 1 xs) 
else x:everyOther (drop 1 xs)

It's telling me there is a possible "spacing error" at the "if" but is this functionally correct. Can I do this?