So, I have a working, templatized linked-queue.... I am simply struggling with an efficient way to allow the user to determine the data type of the queue that is used and created throughout the program... It works fine if I use each type individually... I just need every possibility covered without changing code or re-writing overloaded functions for every data type.... Here are relevant pieces of my code... As I said, no problems with my class member functions.
I already have tried a switch statement that creates x type version of the queue, but that cannot work as later possibilities within the switch "contradict" with other queue data types. I am currently trying if/else if statements, with no errors other than when I try to use the input of x type, it says it is undefined...
// From Source.cpp
#include <iostream>
#include <string>
using namespace std;
#include "LQueue.h"
int mainMenu();
int main()
{
int value;
bool stop = false;
Queue<int> *theQueue;
int choice = mainMenu();
if (choice == 1) {
Queue<int> theQueue;
int dataType;
}
else if (choice == 2) {
Queue<double> theQueue;
double dataType;
}
else if (choice == 3) {
Queue<string> theQueue;
string dataType;
}
else if (choice == 4) {
Queue<char> theQueue;
char dataType;
}
cout << "\n\nHow many items would you like to initially"
<< " populate the queue with? ";
int howMany;
cin >> howMany;
for (int i = 0; i < howMany; i++)
{
cin >> dataType;
theQueue.enqueue(dataType)
}
theQueue.display(cout);
theQueue.dequeue();
theQueue.display(cout);
return 0;
}
int mainMenu()
{
int choice;
cout << "What type of data will you be storing in the queue?\n"
<< "1. integers\n2. decimal numbers\n3. words\n4. chars\n\n";
cin >> choice;
if (choice > 0 && choice < 5)
return choice;
cout << "\n\nInvalid choice\n\n";
mainMenu();
}
// Guess I'll include shown functions from the Queue class file below
//--- Definition of enqueue()
template <typename QueueElement>
void Queue<QueueElement>::enqueue(const QueueElement & value)
{
if (empty())
{
myFront = myBack = new Node(value);
}
else
{
myBack->next = new Node(value);
myBack = myBack->next;
}
}
//--- Definition of dequeue()
template <typename QueueElement>
void Queue<QueueElement>::dequeue()
{
if (empty() == false)
{
Queue::NodePointer oldFront = myFront;
myFront = myFront->next;
delete oldFront;
}
}
//--- Definition of display()
template <typename QueueElement>
void Queue<QueueElement>::display(ostream & out) const
{
Queue::NodePointer ptr;
for (ptr = myFront; ptr != 0; ptr = ptr->next)
out << ptr->data << " ";
out << endl;
}
//--- Definition of front()
template <typename QueueElement>
QueueElement Queue<QueueElement>::front() const
{
if (!empty())
return (myFront->data);
else
{
cerr << "*** Queue is empty "
" -- returning garbage ***\n";
QueueElement * temp = new(QueueElement);
QueueElement garbage = *temp; // "Garbage" value
delete temp;
return garbage;
}
}
Compiler (visual studio 2017) is showing identifier "dataType" is undefined within the following loop:
for (int i = 0; i < howMany; i++)
{
cin >> dataType;
theQueue.enqueue(dataType);
}
2 errors: E0020 and C2065 on the "cin >> dataType;" line, and also another C2065 on the next line
Maybe there is a more efficient way overall of doing this? I am open to any and all suggestions, thank you!
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