Using two lists in a loop to assign two arguments in one function

I have a function with 2 arguments. I would like to display the output using varying inputs of the arguments that can be found in two lists using a loop. I have executed the code successfully with one list (ages) but not with (ages) and (game).

# the below code works for 1 list assignment to the a argument  

for a in ages:
    print(age_price_event(a, 2))

# when I try this to assign the other argument I get an error.

for a in ages b in game:
    print(age_price_event(a, b))

File "", line 1 for a in ages b in game: ^ SyntaxError: invalid syntax

# Here is the function that I wrote

# Function that has two elements 
# a is the age of person
# b is the game
def age_price_event(a, b):
    str(b)
    if b == 1:            # looks to see if it is for 1
        if a < 4:              # if so execute code below
            return (0)    
        elif a < 18:
            return (10)
        else:
            return(15)     #Stop here
    if b==2:                     # looks to see if it is for 2
        if a < 4:                     # if so execute code below
            return (5)
        elif a < 18:
            return (55)
        else:
            return(66)                  #Stop Here
    else:               # if not game is not toady
        return ("That Game is not Today")

# here are the list to be assign to the arguments 
ages = [11, 22, 14, 25]
game = [ 1, 1, 2, 3]

# the below code works for 1 list assignment to the a argument  

for a in ages:
    print(age_price_event(a, 2))

# when I try this to assign the other argument I get an error.

for a in ages b in game:
    print(age_price_event(a, b))

the below code works for 1 list assignment to the a argument

55 66 55 66

when I try this to assign the other argument I get an error.

File "", line 1 for a in ages b in game: ^ SyntaxError: invalid syntax