I have a problem, with a variable that's declared inside an if statement, and i can't use that variable inside another if statement.
This is the first if statement.
if(isset($_POST['submit']))
{
$name = $_POST['name'];
sleep(1);
echo "some text";
?>
This is the second if statement. And this is the one, where i want to use the $name variable
<?php
exit();
}
if(isset($_POST['submit1']))
{
echo $name;
sleep(1);
$pass1 = $_POST['pass1'];
$pass2 = $_POST['pass2'];
$email = $_POST['email'];
$userq = "INSERT INTO game_user (name, email, password) VALUES ('$name', '$email', '$pass1')";
$result = mysqli_query($mysqli,$userq);
}
?>
Any help is appreciated :)
EDIT: Here's the full code as requested :)
<?php
$name = '';
if(isset($_POST['submit']))
{
$name = $_POST['name'];
sleep(1);
echo "Vi mangler lige lidt mere information, før $name kommer på vingerne";
?>
<script>
$(document).ready(function(){
document.getElementById("newbox").style.height = "600px";
$("input").show();
$("sweg").show();
});
</script>
<form method="post">
<input name="pass1" type="password" class="feedback-tand" placeholder="Password" /><br/><br/>
<input name="pass2" type="password" class="feedback-tand" placeholder="Gentag password" /><br/><br/>
<input name="email" type="text" class="feedback-tand" placeholder="Email" /><br/><br/>
<input name="submit1" type="submit" value="OPRET!" id="submit1"/>
</form>
<?php
exit();
}
if(isset($_POST['submit1']))
{
echo $name;
sleep(1);
$pass1 = $_POST['pass1'];
$pass2 = $_POST['pass2'];
$email = $_POST['email'];
$userq = "INSERT INTO game_user (firma, email, password) VALUES ('$name', '$email', '$pass1')";
$result = mysqli_query($mysqli,$userq);
}
?>
<form method="post">
<div class="newcomp">
<input name="name" type="text" class="feedback-tand" placeholder="Airline navn (Dette kan ikke skiftes senere!)" id="tidsrum" />
</div>
<input name="submit" type="submit" value="OPRET!" />
</form>
Also note this code is purely for experimenting.
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