Booleans in If Statements in Python [duplicate]

This question already has an answer here:

• Using global variables in a function other than the one that created them 12 answers

So, I've been coding for a Python 'computer software', one where you basically have a log-in username and password that can be edited. I tried to add a feature that allows you to 'remove' the password, (but is more like skipping it) but it won't work. Here is the code for the 'skipping' procedure:

def Access1(): 
    print("Input first name")
    print("")
    answer = raw_input()
    if(answer.lower() == username and PasswordSkip == True):
        print("")
        print("Access granted")
        List1()
    if(answer.lower() == username and PasswordSkip == False):
        print("")
        print("Access granted")
        Access2()

*Note that 'Access2()' is the function where a password is needed to continue, and 'List1()' is the main menu of the system.

Here is where the boolean is set to True:

def PasswordRemove():
    print("")
    print("Are you sure you want to remove your password, <yes> or <no>?")
    print("")
    key = raw_input()
    if(key.lower() == "yes"):
        PasswordSkip = True
        print("")
        print("Ok, your password has been removed.")
        print("")
        List1()
    elif(key.lower() == "no"):
        DetailsChange()
    else:
        DetailsChange()

And here is how I define and globalise 'PasswordSkip':

PasswordSkip = False

def Startup():
    global PasswordSkip

(the function goes on longer, but has no involvement in the boolean.)

If you need any more infor ation on my code, I'm able to give it to you.

So, when I run my code, it overlooks the if statement about the boolean. If the boolean is True, it should go to a different function. However, it skips the statement because it brings up Access2() (the password function).

Answers aren't urgently needed, but thanks.