Finding majority votes on -1s, 1s and 0s in list - python

How to find the majority votes for a list that can contain -1s, 1s and 0s?

For example, given a list of:

x = [-1, -1, -1, -1, 0]

The majority is -1 , so the output should return -1

Another example, given a list of:

x = [1, 1, 1, 0, 0, -1]

The majority vote would be 1

And when we have a tie, the majority vote should return 0, e.g.:

x = [1, 1, 1, -1, -1, -1]

This should also return zero:

x = [1, 1, 0, 0, -1, -1]

The simplest case to get the majority vote seem to sum the list up and check whether it's negative, positive or 0.

>>> x = [-1, -1, -1, -1, 0]
>>> sum(x) # So majority -> 0
-4
>>> x = [-1, 1, 1, 1, 0]
>>> sum(x) # So majority -> 1
2
>>> x = [-1, -1, 1, 1, 0]
>>> sum(x) # So majority is tied, i.e. -> 0
0

After the sum, I could do this check to get the majority vote, i.e.:

>>> x = [-1, 1, 1, 1, 0]
>>> majority = -1 if sum(x) < 0 else 1 if sum(x)!=0 else 0
>>> majority
1
>>> x = [-1, -1, 1, 1, 0]
>>> majority = -1 if sum(x) < 0 else 1 if sum(x)!=0 else 0
>>> majority
0

But as noted previously, it's ugly: Python putting an if-elif-else statement on one line and not pythonic.

So the solution seems to be

>>> x = [-1, -1, 1, 1, 0]
>>> if sum(x) == 0:
...     majority = 0
... else:
...     majority = -1 if sum(x) < 0 else 1
... 
>>> majority
0

---

EDITED

But there are cases that sum() won't work, @RobertB's e.g.

>>> x = [-1, -1, 0, 0, 0, 0]
>>> sum(x) 
-2

But in this case the majority vote should be 0!!