Python: else ValueError: (Speicifically ValueError In This Case)

I have a question which is unrelated to my code. I'm just curious. Why is it that I (I don't know about you) can only use a ValueError with a try and except loop? for example:

print("What is 1 + 1?")
while(True):
    try:
        UserInput = int(input(("Your answer here:"))
        if(UserInput == 2):
            print("Congratulations you are correct!")
            break
        else:
            print("That is incorrect. Try again!")
    except ValueError:
        print("That is not a number. Try again!")

This works perfectly fine (or at least it should) but, why (if not) would this next piece of code not work.

print("What is 1 + 1?")
while(True):
    UserInput = int(input("Your answer here:"))
    if(UserInput == 2):
        print("Congratulations you are correct!")
        break
    elif(UserInput != 2):
        print("That is incorrect. Try again!")
    else(ValueError):
        print("That is not a number. Try again!")

When I run this I get this error:

Traceback (most recent call last):
  File "python", line 9
    else(ValueError):
        ^
SyntaxError: invalid syntax

I know it is because ValueError only works (I think) with try and except loops but, why can't it not work in the above scenario? I assume they would give the same results but, I don't know everything. Maybe one of you amazingly smart people can tell me my that wont work or an alternative. Thank you for trying to clarify this to me :).