If directory has no files then ... - Linux

I'm looking to see if a directory has no files in it or not. I do not want to take folders into account.

Right now I have ls -1ap | grep -v / | wc -l which will give me the number of files in the directory, but I cant seem to incorporate that into an if statement.

if ls -1ap | grep -v / | wc -l < 1; then echo "one"; else echo "two"; fi

Is there anything I can tweak a bit to get this to work? Thank you