greedy algorithm(with coins) in C

In my code I usede the greedy algorithm in order to use the minimum amaount of coins(for example: i must return $0.41, the minimum amount of coins i can use is 4: 1 - 0,25 ; 1 - 0.10 ; 1 - 0.05 ; 1 - 0.01) There are 4 types of coins: 0.25,0.10,0.05,0.01.

Here is my code:

#include <stdio.h>
#include <cs50.h>

int main(void)
{
    printf("Enter the sum, that you want to return you:");
    float sum = GetFloat();
    float quaters = 0.25;
    float dime = 0.10;
    float nickel = 0.05;
    float penny = 0.01;
    int count_q = 0,count_d = 0,count_n = 0,count_p = 0;


    while(sum<0){
        printf("Incorrect, enter the positive float number");
        sum = GetFloat();
    }

    while(sum > 0){
        if(sum - quaters >=0){
            sum -=quaters;
            count_q +=1;
        }
        else if((sum -quaters <0) && (sum -dime>=0)){
            sum -= dime;
            count_d +=1;
        }
        else if((sum - dime <0) &&(sum - nickel>=0) ){
            sum -= nickel;
            count_n +=1;
        }
        else if(sum - nickel <0){
            sum -= penny;
            count_p +=1;
        }
    }
    printf("The number of quaters: %i\n",count_q);
    printf("The number of dimes: %i\n",count_d);
    printf("The number of nickels: %i\n",count_n);
    printf("The number of pennies: %i\n",count_p);
}

This code calculates how many coins of each type of was used to return the sum. In most cases it works fine.

But sometimes, for example, when i enter the number 1.12 it gives me wrong result:

Enter the sum, that you want to return you:1.12
The number of quaters: 4
The number of dimes: 1
The number of nickels: 0
The number of pennies: 3

I think, that the problem is in last else if statement. But i don't know how can I correct it.