mercredi 26 octobre 2016

Java: Number of Randomly Generated Zeroes

I am having trouble figuring out exactly how to get Java to count the amount of zeroes in the randomly generated list of numbers that goes until it reaches either "-10" or "+10."

I'd appreciate any help,

Thank you.

My Code:

import java.util.Random;

public class RandomWalk 
{
    public static void main(String[] args) 
    {
        Random rand = new Random();

        int position = 0;
        int stepsTotal = 0;
        int zeroesTotal = 0;

         while (position !=10 && position != -10) {
             if (rand.nextDouble() < 0.5) {
                 position--; }
             if (rand.nextDouble() < 0.5) {
                 position++; }
             else {
                 zeroesTotal++ ; }

         stepsTotal++;

         System.out.print(" " + position); }
         System.out.println();
         System.out.println("The final position is: " + position);
         System.out.println("The number of steps taken is: " + stepsTotal);
         System.out.println("There are " + zeroesTotal + " zeroes." );
    }
}

Example output: (I count 4 zeroes, not 21.) (What's it even counting?)

0 0 0 0 1 1 2 3 4 4 4 3 3 4 3 4 3 4 4 5 5 4 4 5 6 6 6 6 5 5 6 7 8 7 7 7 6 6 6 6 7 7 7 7 8 8 8 9 8 9 9 8 7 8 9 9 9 10

The final position is: 10

The number of steps taken is: 58

There are 21 zeroes.

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