Write IF..ELSE in MYSQL

I have a table looked like this

mysql> select * from rc;

    +----+----------------------------+----------------------------+----------------------------+
    | id | business_date              | cutoff_dt                  | recon_dt                   |
    +----+----------------------------+----------------------------+----------------------------+
    |  1 | 2017-03-21 16:50:29.032000 | 2017-03-21 16:50:31.441000 | 2017-03-21 16:50:32.832000 |
    +----+----------------------------+----------------------------+----------------------------+
    1 row in set (0.00 sec)

I want to run query

-Select * from rc where business_date = '2017-03-17' - ifcutoff_dt` is null or empty, it will display null, otherwise display not null

I wrote it into shell script.

#! /bin/bash
mysql -u root -p <<rcard
use rcard;
SELECT * 
(CASE WHEN (cut_off_dt = "NULL")
    THEN
      echo "Null"
    ELSE
       echo "NOT NULL"
END)
from rc WHERE business_date = '2017-03-17';
rcard

But I get error

ERROR 1064 (42000) at line 2: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(CASE WHEN (cut_off_dt = "NULL")
    THEN
      echo "Null"
    ELSE
   ' at line 2

Is it the correct way to write the IF ELSE in MySQL ?