I have an if-elif statement, which I believe not be very efficient:
number = 1000
switch = {
'1': False,
'2': False,
'3': False,
'4': False,
'5': False,
'6': False,
'7': False,
'8': False,
'9': False
}
for i in range(number):
for j in range(number):
if some_condition:
if i <= something and j <= something:
switch['1'] = True
elif i <= something and j <= something:
switch['2'] = True
elif something < i <= something and j <= something:
switch['3'] = True
elif something <= i < something and j < something:
switch['4'] = True
elif something <= i < something and something < j something:
switch['5'] = True
elif something <= i < something and something and j >= something:
switch['6'] = True
elif i >= something and j <= something:
switch['7'] = True
elif i >= something and something < j <= something:
switch['8'] = True
elif i >= something and j >= something:
switch['9'] = True
for i in switch:
if(switch[i] == True):
print(i)
As you can see, the statement looks pretty ugly. Since number is big, it takes almost 2 seconds for the execution.
Is there any way I could lower the CPU time?
I tried this answer, but my statement conditions are different.
Thank you.
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