mardi 22 août 2017

Break out of if while loop in python

I made this counting system in Python 3, https://repl.it/KUG5/1. It's purpose is to choose either addition, substraction, multiplication or division. While also choosing a score system, where the point is to reach the maximum score.

import random
import time

Valg = int(input("\n Addition (1), Subtraction (2), Multiplication (3), Division (4): "))
PoengValgMin = -int(input("\n Choose a minimum score: "))
PoengValgMax = int(input("\n Choose a maximum score: "))

if Valg == 1:

    BrukerPoeng = 0
    Runder = 0

    while BrukerPoeng < PoengValgMax:
        Runder = Runder + 1
        t_start = time.time()

        x = random.randint(5,12)
        y = random.randint(5,12)

        print("\n What is", x, "+", y, "equal to?")
        Svar = int(input("\n Answer here: "))
        if Svar == (x+y):
            BrukerPoeng = BrukerPoeng + 1
            print("\n you are correct, you have now", BrukerPoeng, "points.")
        else:
            BrukerPoeng = BrukerPoeng - 1
            print("\n You were wrong! You have now", BrukerPoeng, "points. The correct answer was", (x+y))
            if BrukerPoeng == PoengValgMin:
                BrukerPoeng = BrukerPoeng + PoengValgMax
                print("You have too many incorrect answers and will be reset.")

    t_slutt = time.time()     
    t_tid = t_slutt - t_start
    print("\n Congratulations! You have now", BrukerPoeng, "points, which you used", Runder, "rounds to complete. The time you used was", round(t_tid,2), "seconds.")

The code above has just the addition part, but my question is: How can I return it to Valg = int(input("\n Addition (1), Subtraction (2), Multiplication (3), Division (4): ")) after the user has succeeded in their choice?

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