Why is the print statement not working for cal and cal2 in switch case?

So the last part seems fair for me but doesn't show any result of cal cal2 in the switch case. I tried to put switch case after the else statement I been stuck in this situation for a day and still couldn't find a solution.

int main(void){
int a;
int b;
int c;
double root;
int result;
int cal;
int cal2;
printf("Type value for a ");
scanf("%d",&a);
printf("Type value for b ");
scanf("%d",&b);
printf("Type value for c ");
scanf("%d",&c);
//Root of quadratic equation
//x=(-b(+-)sqrt(pow(b,2),-4ac))/2a
root=pow(b,2)-(4*a*c);
cal=((-b)+sqrt(root))/(2*a);
cal2=((-b)-sqrt(root))/(2*a);

if(root >=0){
    printf("Type 0 for both roots or 1 for one roots ");
    scanf("%d",result);
    switch(result){
    case 0:
    printf("The calculation of quadratic equation is %d and %d",cal, cal2);
    break;
    case 1:
    printf("One of the calculation of quadratic equation is %d",cal);
    break;
    default:
    printf("Hard\n");
    break;



}
else{
    printf("Error");
    }


}