if 2 elements of a list exists in another list

Full code

cp1=[1,2,3,4,5,6]
cp1=[1,2,3,4,5,6]
cn1=[7,8,9,10,11,12]
cn2=[13,14,15,16,17,18] 
cn3=[19,20,21,22,23,24]
cn4=[25,26,27,28,29,30]
import itertools
sets = [cp1,cn1];
ks = [3,2] 
for i in itertools.product(*[itertools.combinations(set, k) for set, k in zip(sets, ks)]):
    a = i[0]+i[1]
    for i in itertools.permutations(a) :
        i_sum1 = i[0] +  i[1]
        i_sum2 = i_sum1 + i[2]
        i_sum3 = i_sum2 + i[3]
        i_sum4 = i_sum3 + i[4]
        i2_sum1 = i[1] + i[2]
        i2_sum2 = i2_sum1 + i[3]
        i2_sum3 = i2_sum2 + i[4]
        i3_sum1 = i[2] + i[3]
        i3_sum2 = i3_sum1 + i[4]
        i4_sum1 = i[3] + i[4]
        allsum =(i_sum1,  i_sum2,i_sum3,i_sum4, i2_sum1, i2_sum2, i2_sum3, i3_sum1,i3_sum2,i4_sum1)
        if (i_sum1 or  i_sum2 or i_sum3 or i_sum4 or i2_sum1 or i2_sum2 or i2_sum3 or i3_sum1 or i3_sum2 or i4_sum1) not in (cn1 or cn2 or cn3) :
            for b in itertools.product(cn4, repeat=2):
                if (b[0] and b[1]) in allsum :
                    print (i,allsum)

Explanation :

1st - random lists

cp1=[1,2,3,4,5,6]
cn1=[7,8,9,10,11,12]
cn2=[13,14,15,16,17,18] 
cn3=[19,20,21,22,23,24]
cn4=[25,26,27,28,29,30]

2nd - combination betwen 2 lists, using 3 elements of one and 2 of the other one for each result

import itertools sets = [cp1,cn1]; ks = [3,2] for i in itertools.product(*[itertools.combinations(set, k) for set, k in zip(sets, ks)]):

3 - mergeing the results

 a = i[0]+i[1]

4 - permutation of the results

 for i in itertools.permutations(a) :

5 - specific sum of the permutations

i_sum1 = i[0] +  i[1]
    i_sum2 = i_sum1 + i[2]
    i_sum3 = i_sum2 + i[3]
    i_sum4 = i_sum3 + i[4]
    i2_sum1 = i[1] + i[2]
    i2_sum2 = i2_sum1 + i[3]
    i2_sum3 = i2_sum2 + i[4]
    i3_sum1 = i[2] + i[3]
    i3_sum2 = i3_sum1 + i[4]
    i4_sum1 = i[3] + i[4]
    allsum =(i_sum1,  i_sum2,i_sum3,i_sum4, i2_sum1, i2_sum2, i2_sum3, i3_sum1,i3_sum2,i4_sum1)

print only especifics results :

6 - avoid all the the results if any of its sums are in the conjunts, cn2 or cn3 :

(here is where iam having problems)

if (i_sum1 or  i_sum2 or i_sum3 or i_sum4 or i2_sum1 or i2_sum2 or i2_sum3 or i3_sum1 or i3_sum2 or i4_sum1) not in (cn1 or cn2 or cn3) :

7 - Print only the remain results that contain 2 elements of a certain conunct,cn4

for b in itertools.product(cn4, repeat=2):
                if (b[0] and b[1]) in allsum :
                    print (i,allsum)

Output :

the first result is (1, 2, 3, 7, 12) (3, 6, 13, 25, 5, 12, 24, 10, 22, 19) it shows that the 6, and the 7 parts are not working. 6ª should prevent it because it contain (13,12,24,22,19), and 7ª should prevent it because it do not contain two elements of cn4,but only one, "25".

help.