jeudi 29 mars 2018

PHP IF Statement conditions using content of variable [on hold]

I could not find these question, altough i think this was already questioned.

Problem: If you want to build your IF Statement conditions with variables, like:

<?php
//DEFINE IF STATEMENT CONDITIONS INSIDE A VARIABLE
$var =  '$t == 1';
$var .=  ' AND $x == 1';
//END OF DEFINE IF STATEMENT CONDITIONS

//DEFINE VARIABLES
$t = "1";
$x = "2";
//END OF DEFINE VARIABLES

//NOW CHECK THE IF STATEMENT, YOU CAN SEE THE CONDITION SHOULD BE FALSE BECAUSE $x != 1
if( print($var) == TRUE)
{   echo "TRUE";    }
else
{   echo "FALSE";   }
//I KNOW THE CODE (print($var) == TRUE) WONT WORK, ONLY SHOWN FOR A BETTER UNDERSTANDING
?>

The If statement above just proofs if the variable exists, but i want to proof if the content of the variable is true: $t == 1 AND $x == 1.

The IF statement in the code above should be similar to:

if( $t == 1 AND $x == 1)
{   echo "TRUE";    }
else
{   echo "FALSE";   }

I tried a lot. Now i would be happy for a solution, which includes an If statement in the form of If (PROOF CONTENT OF VARIABLE) {}.

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