How can I use switch instead of multiple if statements?

I was wondering if it is possible to rewrite multiple if statements into a switch.

The problem is that a switch runs:

1. all code after a case passes a check. Which is why the case statement runs all code after the first case.

   let arr = [1, 3];
   
   if( arr.includes(1) === true ) {
     console.log('if 1');
   }
   if( arr.includes(2) === true) {
     console.log('if 2');
   }
   if( arr.includes(3) === true) {
     console.log('if 3');
   }
   
   
   switch( true ){
     case arr.includes(1):
       console.log('switch 1');
     case arr.includes(2): 
       console.log('switch 2');
     case arr.includes(3): 
       console.log('switch 3');
   }
   

   2. if a switch has breaks in every case, it runs a single case, that passes the test.

let arr = [1, 3];

if( arr.includes(1) === true ) {
  console.log('if 1');
}
if( arr.includes(2) === true) {
  console.log('if 2');
}
if( arr.includes(3) === true) {
  console.log('if 3');
}


switch( true ){
  case arr.includes(1):
    console.log('switch 1');
    break;
  case arr.includes(2): 
    console.log('switch 2');
    break;
  case arr.includes(3): 
    console.log('switch 3');
    break;
}

So the question is: How can I rewrite multiple if statements into a single switch statement?

If I can't: Is there another more elegant syntax than the multiple if statements, that makes it apparent that I am making similar comparisons?