Python Generator - Function unintendedly returning a generator [duplicate]

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• Why can't you toggle a function generator's behavior with a kwarg? [duplicate] 2 answers

This function is a test function made for the purpose of understanding another problem I'm having in some other code. I am trying to figure out why a generator is being returned in the case where the list comprehension code should execute rather than the generator code.

def test(a, gen=False):

    if not gen:
        return [x for x in range(a)]
    else:
        for i in range(a):
            yield i


print(test(10))
print(test(10, gen=True))



<generator object test at 0x7f20882a0bf8>
<generator object test at 0x7f20882a0bf8>