Why does this if then else statement always value to the else in java [duplicate]

This question already has an answer here:

• How do I compare strings in Java? 23 answers

This code is supposed to evaluate to "Its me!..." statement if the parameters inputed are "White" AND "Fat" AND "Used" but for some reason I keep getting "Oh, shucks" regardless of what I input. Im not sure how to get it to work properly.

Does it have to do something about the way I initialized the variables or the way I implemented the scanner?

public static void main(String[] args)      {       
    String color = "";
    String slenderOrFat = "";
    String usedOrNew = "";

    System.out.println("What Color? ");             // Prompting the user for a color input
    Scanner whatColor = new Scanner(System.in);     // Reading from System.in
    color = whatColor.nextLine();                   // Setting variable to user input value
    System.out.println(color);

    System.out.println("Slender or Fat? ");         // Prompting the user for a "Slender" or "Fat" input
    Scanner slender_fat = new Scanner(System.in);   // Reading from System.in
    slenderOrFat = slender_fat.nextLine();          // Setting variable to user input value
    System.out.println(slenderOrFat);

    System.out.println("Used or New? ");            // Prompting the user for a "Used" or "New" input
    Scanner used_new = new Scanner(System.in);      // Reading from System.in
    usedOrNew = used_new.nextLine();                // Setting variable to user input value
    System.out.println(usedOrNew);

    if (color == "White" && slenderOrFat == "Fat" && usedOrNew == "Used" ){ //The conditions of the selection control structure 
        System.out.println("It's me! It's me! It's me!");                   //This is printed if Stubee is found
    }
    else{
        System.out.println("Oh, shucks");                                   //This is printed otherwise
    }

}

}