please I need help with this code of mine. I am trying to display only fields from my SQL table with contents in my carousel. I do not want the carousel to always slide into an empty item and display a broken photo icon at the top right corner.
$query = "SELECT * FROM property where id = '".$id."' ";
$result_new = mysqli_query($con, $query) or die("Could not execute query");
while ($row = mysqli_fetch_array($result_new))
{
$picture1 = "propertyphotos/".$row['picture1'];
$picture2 = "propertyphotos/".$row['picture2'];
$picture3 = "propertyphotos/".$row['picture3'];
$picture4 = "propertyphotos/".$row['picture4'];
if(!empty($row['picture1']))
{
$pic1= '<div class="item active">
<img class="s-property-image" src="<?php echo $picture1; ?>" />
</div>';
}
if(!empty($row['picture2']))
{
$pic2= '<div class="item active">
<img class="s-property-image" src="propertyphotos/<?php echo $picture2; ?>" />
</div>';
}
if(!empty($row['picture3']))
{
$pic3= '<div class="item active">
<img class="s-property-image" src="propertyphotos/<?php echo $picture3; ?>" />
</div>';
}
if(!empty($row['picture4']))
{
$pic4= '<div class="item active">
<img class="s-property-image" src="propertyphotos/<?php echo $picture4; ?>" />
</div>';
}
}
?>
<?php echo $pic1; ?>
</div>
Or if there is a better to this i would love to learn. thank you
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