Python: Is there a way to print even numbers within an unknown range and without if statement?

I have a homework to do in python class and was given this question:

Make a program that gets 2 numbers from the user, and prints all even numbers in the range of those 2 numbers, you can only use as many for statements as you want, but can't use another loops or if statement.

I understand that I need to use this code:

for num in range (x,y+1,2):
    print (num)

but without any if statements, I can't check if the value x inserted is even or odd, and if the user inserted the number 5 as x, all the prints will be odd numbers.

I also tried to enter each number to a tuple or an array, but I still can't check if the first number is even to start printing.

def printEvenFor(x,y):
    evenNumbers =[]
    for i in range (x,y+1):
        evenNumbers.append(i)
    print (evenNumbers[::2])

or

def printEvenFor(x,y):
    for i in range (x,y+1,2):
        print(i,",")

I expect the output of printEvenFor(5,12) to be 6,8,10,12 but it is 5,7,9,11