jeudi 21 mai 2020

If statement based on whether a variable is equal to either value in a randomized array

I want to build an if statement in which the if criteria is based on an equality test of whether a variable equals any of several values. However, I do not want to hardcode the test values, but to pass an array of values that had been randomly subset earlier.

First, I get the set of randomized values by subsetting/sampling 5 values out of an array of 15 values. Basically, I'm using this excellent solution.

function getRandomSubarray(arr, size) {
    var shuffled = arr.slice(0), i = arr.length, temp, index;
    while (i--) {
        index = Math.floor((i + 1) * Math.random());
        temp = shuffled[index];
        shuffled[index] = shuffled[i];
        shuffled[i] = temp;
    }
    return shuffled.slice(0, size);
}

var x = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15];
var fiveRandomMembers = getRandomSubarray(x, 5);

Then, I want to pass fiveRandomMembers to test whether a variable is equal to any of the values in fiveRandomMembers's array. Then do something. To this end, I want to use this solution.

var L = function()
{
    var obj = {};
    for(var i=0; i<arguments.length; i++)
        obj[arguments[i]] = null;

    return obj;
};

if(foo in L(fiveRandomMembers)) {
/// do something
};

Unfortunately, this doesn't work for me. I must admit that the implementation of this code is within a Qualtrics survey, so the problem might be nuanced to the Qualtrics platform, and that's the reason it isn't working for me. I'm newbie to JavaScript so I apologize if this is a trivial question. But I believe that my code is problematic even in plain JavaScript (that is, regardless of Qualtrics), and I want to figure out why.

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