The case of a faulty loop

Hi in my case of of my code i want a certain output that i am looking for but i cannot seem to figure it out. I feel like one of my loops is messing it up or if i have to use an 'else' in either the case 0: or case 4:

heres my code:

    #include <stdio.h>
#define SIZE 4

struct Employ {
    int ID;
    int age;
    double salary;
};

int main(void) {
    struct Employ emp[SIZE];                                //make Employ structured variable and initialize;
    int option = 1;                                         //option variable
    int nEmp = 0;                                           //counting how many employee we have so far
    int i;
    int searchedI;
    int check;                                              //to check each variable is valid
    int sID;                                                //searching ID
    printf("---=== EMPLOYEE DATA ===---\n\n");
    while (option != 0) {
        printf("1. Display Employee Information\n");
        printf("2. Add Employee\n");
        printf("3. Update Employee Salary\n");
        printf("4. Remove Employee\n");
        printf("0. Exit\n\n");
        printf("Please select from the above options: ");
        scanf("%d", &option);
        printf("\n");
        switch (option)
        {
        case 1:                                             //print employee information
            printf("EMP ID  EMP AGE EMP SALARY\n");
            printf("======  ======= ==========\n");
            for (i = 0; i < nEmp; i++) {
                printf("%6d%9d%11.2lf\n", emp[i].ID, emp[i].age, emp[i].salary);
            }
            printf("\n");
            break;
        case 2:                                             //add employee
            printf("Adding Employee\n");
            printf("===============\n");
            if (nEmp == SIZE) {                             //check if we already got maximum employee
                printf("ERROR!!! Maximum Number of Employees Reached\n\n");
            }
            else {                                          //otherwise go on adding
                check = 1;
                while (check) {
                    printf("Enter Employee ID: ");
                    scanf("%d", &emp[nEmp].ID);
                    printf("Enter Employee Age: ");
                    scanf("%d", &emp[nEmp].age);
                    printf("Enter Employee Salary: ");
                    scanf("%lf", &emp[nEmp].salary);
                    if (emp[nEmp].ID < 0 || emp[nEmp].age < 0 || emp[nEmp].salary < 0) printf("\nAll number should be positive\n\n");   //check if everything is positive number
                    else check = 0;
                }
                printf("\n");
                nEmp++;
            }
            break;
        case 3:                                             //update employee
            printf("Update Employee Salary\n");
            printf("======================\n");
            if (nEmp == 0) {                                //in case there is no employee yet
                printf("\nNo employee to update\n\n");
                break;
            }
            do
            {
                check = 1;
                printf("Enter Employee ID: ");
                scanf("%d", &sID);
                for (i = 0; i < nEmp; i++)
                {
                    if (emp[i].ID == sID) break;
                    else if (i == nEmp - 1) printf("\nID not found\n\n");
                }
                if (i != nEmp) {
                    printf("The current salary is %.2f\n", emp[i].salary);
                    printf("Enter Employee New Salary: ");
                    scanf("%lf", &emp[i].salary);
                    check = 0;
                    printf("\n");
                }
            } while (check);
            break;
        case 4:                                             //remove employee
            printf("Remove Employee\n");
            printf("===============\n");
            if (nEmp == 0) {                                //in case there is no employee yet
                printf("\nNo employee to remove\n\n");
                break;
            }
            do
            {
                check = 1;
                printf("Enter Employee ID: ");
                scanf("%d", &sID);
                for (i = 0; i < nEmp; i++)
                {
                    if (emp[i].ID == sID) break;
                    else if (i == nEmp - 1) printf("\nID not found\n\n");
                }
                if (i != nEmp) {
                    check = 0;
                    searchedI = i;
                    printf("Employee %d will be removed\n\n", emp[searchedI].ID);
                    for (i = searchedI; i < nEmp; i++)
                    {
                        if (i != nEmp - 1) emp[i] = emp[i + 1];
                        else emp[i].ID = 0;
                    }
                    nEmp -= 1;
                }
            } while (check);
            break;
        case 0:                                             //exit
            printf("Exiting Employee Data Program. Good Bye!!!\n");
            break;
        default:                                            //not valid option input
            printf("ERROR: Incorrect Option: Try Again\n\n");
            break;
        }
        //if (option != 0) option = -1;
    }
    return 1;
}

Heres the output i am looking for in the end. Note that at the end of the output the 666 replaces 333 in its spot

====== ======= ==========
222 22 22222.22
333 33 99999.99
444 44 44444.44
555 55 55555.55
1. Display Employee Information
2. Add Employee
3. Update Employee Salary
4. Remove Employee
0. Exit
Please select from the above options: 4
Remove Employee
===============
Enter Employee ID: 789
*** ERROR: Employee ID not found! ***
Enter Employee ID: 987
*** ERROR: Employee ID not found! ***
Enter Employee ID: 333
Employee 333 will be removed
1. Display Employee Information
2. Add Employee
3. Update Employee Salary
4. Remove Employee
0. Exit
Please select from the above options: 1
EMP ID EMP AGE EMP SALARY
====== ======= ==========
222 22 22222.22
444 44 44444.44
555 55 55555.55
1. Display Employee Information
2. Add Employee
3. Update Employee Salary
4. Remove Employee
0. Exit
Please select from the above options: 2
Adding Employee
===============
Enter Employee ID: 666
Enter Employee Age: 66
Enter Employee Salary: 66666.66
1. Display Employee Information
2. Add Employee
3. Update Employee Salary
4. Remove Employee
0. Exit
Please select from the above options: 1    
EMP ID EMP AGE EMP SALARY
====== ======= ==========
222 22 22222.22
666 66 66666.66
444 44 44444.44
555 55 55555.55