Ignoring condition for a value in the list using python

my function is printing passed if the condition becomes successful for the items on the list. if not then it will print failed

list1 = [2,3,4,5,6,7,8,9,10,11,12,13,14,16]

for n in list1:
  if 15 > n:
    print("passed")
  else:
    print("failed")

It is giving the correct output. for value 16 in the list1, it is printing failed

Current output:

passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
failed   

Is it possible that for value 16 in the list1 also, it should ignore failed and print passed only

Expected output: printing passed for value 16 in the list1

passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed
passed