Counting substring characters in string

I'm writing a function that takes an input string consisting of a mix 'o' 'g' and 'c'. For each of these characters in the string, a certain symbol is printed. However, for the 'g' character, id like to count how many g's are in a row in the string. Here is the code I have so far:

void printSymbol(char *str) // takes
{
  int i; // counter for entire string
  int k; // counter for substring ('g' char)
  int count = 0; //stores amount of consecutive g's in substring

  for (i = 0; str[i] != '\0'; i++) //looping until null term.
  {
    if (str[i] == 'o')
      printf("==========\n"); //symbol for o
    if (str[i] == 'c')
      printf(" ~~~~~~~~ \n"); //symbol for c
    if (str[i] == 'g') //if character is g
    {
      for(k = i; str[k] == 'g'; k++) //will loop through string starting at first g until next character is NOT g
      {
        count++; //count amount of consecutive g
      }
      printf("%d\n", count); //printing number of g's in a row
      if (count % 3 == 2) //All of these if statements are printing.
        printf("R==2\n");
      if (count % 3 == 1)
        printf("R == 1\n");
      if (count % 3 == 0)
        printf("R == 0\n");

      count = 0; // resets count for next set of consecutive g's in string
    }
  }
}

The problem I'm having is that it is printing all if statements in the for loop for the g char. If there are 3 g's in a row, it will print R = 0, then R = 2, and R = 1, because it will loop through each g and thus the remainder is changing. How do I stop this? Id like to record the remainder for the entire set of consecutive g's one time. So if there are 3 g's, Id like to print R = 0, and then reset the counter var.