Effective way to write a series of if statements in Python?

I have a piece of code that I would like to re-write in order for it to be more effective. I am working in Python, and there is not switch-break statement like in Java, but I feel something of a similar structure would work. The piece of code in particular I am talking about is:

def update(arm, array1, array2, array3, array4, array5, array6, array7, array8, array9, array10):
    # If the array is empty, add a zero
    if not array1:
        array1.append(0)
    if not array2:
        array2.append(0)
    if not array3:
        array3.append(0)
    if not array4:
        array4.append(0)
    if not array5:
        array5.append(0)
    if not array6:
        array6.append(0)
    if not array7:
        array7.append(0)
    if not array8:
        array8.append(0)
    if not array9:
        array9.append(0)
    if not array10:
        array10.append(0)

    # If the chosen arm doesn't match, then add the last value that was added before to the end
    if arm != 0:
        array1.append(array1[-1])
    if arm != 1:
        array2.append(array2[-1])
    if arm != 2: 
        array3.append(array3[-1])
    if arm != 3:
        array4.append(array4[-1])
    if arm != 4:
        array5.append(array5[-1])
    if arm != 5:
        array6.append(array6[-1])
    if arm != 6:
        array7.append(array7[-1])
    if arm != 7:
        array8.append(array8[-1])
    if arm != 8:
        array9.append(array9[-1])
    if arm != 9:
        array10.append(array10[-1])

In general, what is a good way to avoid writing a series of if-statements like this in Python while also going through and checking each of these arrays for this particular function?