node1 and node2 are nodes of a linked list.
Node* node1, Node* node2;
int carry = 0;
int sum;
sum = carry + (node1 ? node1->data : 0) + (node2 ? node2->data : 0);
Since x ? y : z works like if(x) y else z I tried
if (node1 && node2)
sum = carry + node1->data + node2->data;
else if(node1 && !node2)
sum = carry + node1->data;
else if(!node1 && node2)
sum = carry + node2->data;
else if(!node1 && !node2)
sum = carry;
Can we use nodes as if they were booleans like this? If not, how can I write this statement without using the question mark?
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