(Python) If statement to always search for specific class name to be true and present and only then will it run the code below it

I have been struggling on this for a while.

I want it to always be searching for this class name and trigger the code below it when the class is found. I dont want the script below it to be active until the class name is present. Until a pop up box is present for example.

I am using selenium and webdriver.

I am trying to make this work:

while not driver.find_element_by_class_name("rc-anchor-pt"):
    sleep(10)
    #driver.refresh()
    #time.sleep(random.randint(2,3))

#code below it I want to run whenever the class name is found and present

   driver.find_element_by_xpath("/html/body/div/div/div[3]/div/button").click()
    #get the mp3 audio file
   src = driver.find_element_by_id("audio-source").get_attribute("src")
   print("[INFO] Audio src: %s"%src)
   #download the mp3 audio file from the source
   urllib.request.urlretrieve(src, os.getcwd()+"\\sample.mp3")
   sound = pydub.AudioSegment.from_mp3(os.getcwd()+"\\sample.mp3")
   sound.export(os.getcwd()+"\\sample.wav", format="wav")
   sample_audio = sr.AudioFile(os.getcwd()+"\\sample.wav")
    r= sr.Recognizer()