mercredi 9 décembre 2020

If condition is automatically fulfilling in python

I have written a program and at the end I have written a code for the user to rate my program, but it has some issues please help:

while True:
    RR = input("What would you rate this program(?/5): ")
    if RR.isnumeric:
        rating = int(RR)
        if rating >= 5:
            print("Looks like you are highly satisfied with this program :D")
            break
        elif rating == 4 or rating == 3:
            print("Ohh! Next time I'll try my best to change this '",rating,"' into 5 ;D")
            break
        elif rating == 1 or rating == 2:
            print("I am sorry if I wasn't good, I'll try my best next time :|")
            break
    else:
        print("Invalid Rating, Try again...")
        continue

Result

What would you rate this program(?/5): g
ValueError: invalid literal for int() with base 10: 'g'

What I want is that if someone enters a text instead of a number then it tells that it's an invalid input and continues the loop. How can I get this?

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