Breaking out of For Loop and If Statement

My list:

listOfMovies=[the Slow and Confused 9, Somebody, Gorilla vs. King, The Blundering 3: Boss Made Me Do It]

I am trying to take an input and if there is a match to the list, the function will print out the object.

If there is no match, the function will print out and ask if I would like to search again or return to the mainmenu.

No results found
1. Search again
2. Return to Main Menu

Currently I am able to print the matches however, I also print out the no results as well.

If there are no matches with the input, I want No results to be printed.

I would like to print out the matches and skip printing the no results found.

My code is:

def DisplayMovie( movie, i  ):
     print ( "Movie Name: " + str(movie[i].getName()) + ",", "Category:" , movie[i].getCategory())
     return


def SearchBasedOnName(searchString, listOfMovies):
     for i in range ( len(listOfMovies) ):    
          if (searchString.lower()  in  listOfMovies[i].getName().lower()):
                            DisplayMovie( listOfMovies, i)
               
     print("\nNo results found")
     print("1. Search again")
     print("2. Return to Main Menu")
     option3input = input("")
     if option3input == "1":
             searchString = input("\nPlease enter your search input: \n")
     elif option3input == "2":
             printMenu()

searchString = input("\nPlease enter your search input:")
SearchBasedOnName(searchString, listOfMovies)

The output I get:

Please enter your search input: king

Movie Name: Gorilla vs. King

No results found
1. Search again
2. Return to Main Menu