At my work I tried to use this construction:
if (repl && (repl = replaced.count(*l))) {
// repl isn't used here
...
}
and in my mind it should work the same way as
bool newRepl = replaced.count(*l);
if (repl && newRepl) {
// repl isn't used here
...
}
repl = newRepl;
because expressions in &&
evaluate from left to right, but unexpectedly it's not.
Is it a not specified construction in C++ or I don't correctly understand how it should work?
Example of code with a problem:
std::set<int> set{3, 4, 6};
bool repl = false;
for (size_t i = 3; i < 7; ++i) {
if (repl && (repl = set.count(i))) {
std::cout << "strangeif" << std::endl;
}
}
output:
std::set<int> set{3, 4, 6};
bool repl = false;
for (size_t i = 3; i < 7; ++i) {
bool newRepl = set.count(i);
if (repl && newRepl) {
std::cout << "strangeif" << std::endl;
}
repl = newRepl;
}
output: strangeif
Aucun commentaire:
Enregistrer un commentaire