[1]:-the code i entered in python 3.5 (new file-not idle) [2]:-this is what i get when i run module and type 2. When i click run module and type 2, it prints what i have kept for else : .... etc. check it out in [2]. Please help me out with my problem.But when i exchanged if input == 2 with if input != 2 , and type 2 , it shows what i have written for if info != 2. how's that possible? [1]http://ift.tt/1OmHo33 [2]http://ift.tt/1PqxYsw
dimanche 27 décembre 2015
I can't solvebasic code form in php
I am new in Php world. This is my first question ever in any form. Please tell me what errors in my page. When i submit form no result came out. Please give me any solution.
I try to follow this video. https://www.youtube.com/watch?v=15Ucddc2ksM
enter code here
<!Doctype html>
<html>
<head>
<title> My page </title>``
</head>
<body>
<p style="font-weight:bold">hello1 world</p>
<?php
// Restaruant open at 8
// Restaruant from 8-11
// Lunch from 11-4
// closes at 4
$launch_menu = "Nashta <br />
halwa <br /> gosher <br /> ";
$breakfast_menu = "Launch <br />
sugar <br /> meat <br /> ";
if(isset($_post['time'])) {
$time = $_post['time'];
if($time < 8 or $time >= 16 ) {
echo "sorry, we are closed <br />" ;
}
else{
echo "Hi, what would you like order <br /> ";
if($time < 11){
echo $breakfast_menu;
}
else if ($time < 16)
{
echo $launch_menu;
}
}
}
?>
<form action='index.php' method='post'>
What time is it? <input type='text' name='time' /> <br />
<input type='submit' value='Submit'>
</form>
</body>
</html>
samedi 26 décembre 2015
Return with a for loop
The code i am using is below. As far as i am aware the logic of the code is fine but when the return is after the print for the char B then the i within the for loop wont increment. If i remove the return statement then the for loop will increment as i wanted it too, however i need the method to end if the B/W is printed so i need the return to be present. Any help is greatly appreciated i've been trying to work out whats wrong for hours now.
if(currentCodeString.contains("" + currentGuessChar)) {
for (int i = 0; i < codeLength; i++) {
System.out.println("" + i);
//System.out.println(currentGuess[i] + " - " + currentCode[i]);
if(checkPins(currentGuess[i], currentCode[i])) {
System.out.print("B");
return;
}
}
System.out.print("W");
return;
}
How to check if element is greater than another by certain %
I need to put a check in a C program to check if value[1] > value[2] by a certain % (in this case 15%) . But am struggling to come up with the simplest method?
Thanks,
'if statement' not firing on mobile?
This works fine on everything except for mobile. Is there a reason for this? How do I get around it?
$(document).ready(function()
var my_var = 10;
if(! my_var =="") {
//do my code
}
});
if statement to indicate whether a market has gone up or down
I have a dataset from library(ISLR) and I would like to make my own up and down, but my if statement always fail, any help would be appreciated:
library(ISLR)
attach(Smarket)
for (i in 1:nrow(Smarket)){
Smarket$myown = ()
if (Smarket[i, "Today"]>0) { Smarket$myown = "Up"
} else { Smarket$myown = "Down"
}}
Please note that if I use the statement ifelse then the issue is solved, but I want your help to MODIFY the above code, so I may learn
Smarket$myown = ifelse(Smarket[, "Today"]> 0, "Up", "Down")
How can I insert a if function in an array
I have an array
$data_array =
array
(
"limit" => $limit,
"page_number" => $page,
"books" => $books
);
I want that if $books is set then the array should be
array
(
"limit" => $limit,
"page_number" => $page,
"books" => $books
);
and if the variable $books is not set the array should be
array
(
"limit" => $limit,
"page_number" => $page
);
please can anybody help me.