why these following c programme do not follow the code execution order?

Why the if condition in the following program do not follow the sequence specified? i.e, when r equals to k , either the b or g should not increment its value but it does increase its value by one.

#include <stdio.h>
int main(void){
  int T;
  scanf("%d",&T);

  while(T>0)
    {
    int R,G,B,k,i,r=0,g=0,b=0,count=0;
    scanf("%d %d %d",&R,&B,&G);
    scanf("%d",&k);
    if(k<=R || k<=G || k<=B)
      {
      for(i=1;i<=k;i++)
        {
        if(r<R && (b!=k || g!=k) )
          {
          r++;
          }
        if(b<B && (r!=k || g!=k) ) // these conditions has to be executed 
          {
          b++;
          }
        if(g<G && (r!=k || b!=k) )
          {
          g++;
          }  
        }

      count=r+g+b;

      printf("%d\n",count);
      }
    T--;
    }
  return 0;
}