So i'm trying to make a programm that repeatedly asks the user to guess a number. He then loses (or the programm quits) if one of these conditions are true:
- user uses the number 5
- user uses a number bigger then 10
- user uses a number that is equal to the number of the guessed times he has already guessed
- user has only 10 tries
Here is the problem, if I input the number 5 as my first guess the else function works and cout outputs the strings but if I first guess something else and then use the number 5 for some reason the program just quits without outputting the string in the last else block.
Here is were I would love to see some feedback on what I need to change so that I can input multiple user input and then still us the number 5 to get the cout strings in the else function. Thank you in advance :)
Here is the code:
#include <iostream>
using namespace std;
int main() {
int input = 0;
short counter = 0;
cout << "Hello fellow PC-User why don't you guess a number that is between 1-10 ?" << endl;
cout << "Come on give it a try!\nOnly two conditions (maybe three) don't use the Number 5 and only Numbers 1-10!\nNow let's go!!!" << endl;
cin >> input;
if(input != 5 && input < 10){
while(input != 5 && input < 10) {
++counter;
cout << "Nice you guessed " << counter << flush;
if (input > 1){
cout <<" times!" << flush;
} else{
cout << " time!" << flush;
}
cout << "\nNow go at it again just don't used the number the times u tried bro!" << endl;
cin >> input;
if(counter == 10){
cout << "Damn that motivation doe...well what can I say\n I give up \n U win." << endl;
return 0;
} else if(counter == input){
cout << "Don't do it..." << endl;
return 0;
}
}
} else {
cout << "Yo! You weren't supposed to use that number!\nNow u looooose" << endl;
}
return 0;
}
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