samedi 6 mai 2017

Lua comparing multiple integers

I want to compare if n1-10 one of them is = box then write nx1 and ny1 and so on ... what could I do to compare them faster . the below way will take years from me

 box=readString('[[[[[_name]+11c]+670]+394]+2fc]+1c',20)
    n1=readString('[_player]+184',20)
    n2=readString('[_player]+f94',20)
    n3=readString('[_player]+1da4',20)
    nx1= readInteger('[_player]+48d8')
    nx2= readInteger('[_player]+56e8')
    nx3= readInteger('[_player]+64f8')

    ny1= readInteger('[_player]+48dc')
    ny2= readInteger('[_player]+56ec')
    ny3= readInteger('[_player]+64fc')

    if box =n1 or n2 or n3   --lets say n1=box  
    then    writeInteger('[_player]+28c',n1x) 
            writeInteger('[_player]+28c',n1y) 

    if box =n1 or n2 or n3   --lets say n2=box  
    then    writeInteger('[_player]+28c',n2x) 
            writeInteger('[_player]+28c',n2y) 

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