I am learning to create a block of 'if' statements to check certain conditions and I want them to identify if the list has empty quote marks in it.
so for example:
favourite_fruit = []
if len(favourite_fruits) == 0:
print('Fruits are an important part of one's diet')
###This code works which is great as long as the list is empty in terms of it's length.
if the list isn't empty and they have something like: 'apple' in it, but another fruit like 'dates' is missing, then I would tell it to say:
if 'dates' not in favourite_fruit and len(favourite_fruit) != 0:
print ('Have you tried Dates? They are high in fibre, a good source of which, can help prevent constipation by promoting bowel movements.')
But the problem is if I type:
favourite_fruit = ['']
The length of this list is 1 but there is nothing in it so it will print out the dates quote but not the 'fruits are important' quote.
Is there a way for me to get python to identify there is nothing actually written in the list?
I am pretty much a beginner so I am still learning
Here is what I have tried though:
favourite_fruit = ['']
if 'dates' not in favourite_fruit and len(favourite_fruit) != 0 and favourite_fruit != "" and favourite_fruit != "\"\"" and favourite_fruit != '' and favourite_fruit != '\'\'':
print ('Have you tried Dates? They are high in fibre, a good source of which, can help prevent constipation by promoting bowel movements.')
But it still isn't working.
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