Is there a better way to solve this than using multiple for loops?

I'm trying to write a program that will score the Keirsey Bates personality test. The user passes a string that's 70 characters long and the string is evaluated based on the scoring method here.

I've written the program and everything works, but I know that it's not the most efficient/elegant way to do this. What I did was use 4 separate for loops to calculate the number of 'A's and 'B's in each column (for all columns except the first one, I used a nested for loop because I needed to add two columns together). For class standards, our method cannot exceed 50 LOC and our complete program (without the unit tests) must not exceed 100 LOC; repetition in code is also not allowed.

In my code I can see that there's a lot of repetition/similarity with the for loops and if/else statements. But I can't seem to think of a cleaner way to solve the problem. If someone could point me in the right direction, that would be awesome!

Here is the program I've written:

public class KeirseyScorer {
   public static String evaluateSurvey(String responses) {
      int surveyLength = 70;
      String first = "", second = "", third = "", result = "";
      int numAFirst = 0, numBFirst = 0, numASecond = 0, numBSecond = 0, numAThird = 0, numBThird = 0, numALast = 0, numBLast = 0;

      if(responses.length() != surveyLength || !responses.matches("[AB]*")) {
         result = "ERR!";
      }
      else {
          //Gets first letter in personality type
          for(int i = 0; i < surveyLength; i+= 7) {
            if(responses.charAt(i) == 'A') {
               numAFirst++;
            }
            else {
               numBFirst++;
            }
         }
         if(numAFirst > numBFirst) {
            first = "E";
         }
         else if(numAFirst == numBFirst) {
            first = "X";
         }
         else {
            first = "I";
         }
         //Gets second letter in personality type
         for(int j = 2; j < surveyLength; j+= 7) {
            for(int k = 1; k < surveyLength; k += 7) {
               if(responses.charAt(k) == 'A') {
                  numASecond++;
               }
               else {
                  numBSecond++;
               }
            }
         }
         if(numASecond > numBSecond) {
            second = "S";
         }
         else if(numASecond == numBSecond) {
            second = "X";
         }
         else {
            second = "N";
         }
         //Gets third letter in personality type
         for(int m = 4; m < surveyLength; m+= 7) {
            for(int l = 3; l < surveyLength; l += 7) {
               if(responses.charAt(l) == 'A') {
                  numAThird++;
               }
               else {
                  numBThird++;
               }
            }
         }
         if(numAThird > numBThird) {
            third = "T";
         }
         else if(numASecond == numBSecond) {
            third = "X";
         }
         else {
            third = "F";
         }
         //Gets last letter and concats everything together for personality
         for(int o = 6; o < surveyLength; o+= 7) {
            for(int n = 5; n < surveyLength; n += 7) {
               if(responses.charAt(n) == 'A') {
                  numALast++;
               }
               else {
                  numBLast++;
               }
            }
         }
         if(numALast > numBLast) {
            result = first + second + third + "J";
         }
         else if(numALast == numBLast) {
            result = first + second + third + "X";
         }
         else {
            result = first + second + third + "P";
         }
      }
      return result;
   }
}