Perl 6 - Word 'if' interpreted as 'if()' function call. Parens not allowed

So I discovered that writing an if statement with parentheses in Perl 6 results in it throwing this error at me:

===SORRY!===
Word 'if' interpreted as 'if()' function call; please use whitespace instead of parens
at C:/test.p6:8
------> if<HERE>(True) {
Unexpected block in infix position (two terms in a row)
at C:/test.p6:8
------> if(True)<HERE> {

This makes me assume that there is some sort of if() function? However, creating and running a script with if(); in it produces the following compiler error:

===SORRY!===
Undeclared routine:
    if used at line 15

So like what's the deal?

I read here http://ift.tt/1PECvpE that parens are optional but that seems to not to be the case for me.

My if statements do work without parens just wondering why it would stop me from using them or why it would think that if is a subroutine because of them.