syntax error, unexpected 'else' (T_ELSE), line 40 [duplicate]

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• PHP Parse/Syntax Errors; and How to solve them? 10 answers

I've got this code but it gives me a syntax error. line 40 } else {

foreach ($obj->response->games as $r)
{
  if ($r->appid == 730)
    $found = true;
}
if ($found)
{
  if($allow)
  {
  $referralUser = \DB::table('users')->where('referral_code', $code)->first();
  $user = \App\User::findOrFail(\Auth::user()->id);
  $user->referral = $referralUser->id;
  $user->save();

  $balance = new \App\Balance;
  $balance->user_id = \Auth::user()->id;
  $balance->type = "increment";
  $balance->value = 100;
  $balance->data = $code;
  $balance->source = "referral.code";
  $balance->save();

  $balance = new \App\Balance;
  $balance->user_id = $referralUser->id;
  $balance->type = "increment";
  $balance->value = 5;
  $balance->data = $code;
  $balance->source = "referral.use";
  $balance->save();
  }
  else
  {
  return \Response::json(["success" => false, "msg" => "You must be level 5 or above to use referral system!"], 500);
  }
}
else
{
return \Response::json(["success" => false, "msg" => "You do not have CSGO."], 500);
} else {
  return \Response::json(["success" => false], 500);
}
}

I am looking on it for 4 days straight atm. Please help me out!

Thanks!