I had a little debug intercept that said
if (true)
throw new Exception()
DoStuff();
However the compiler warned me that DoStuff() was unreachable code. So were the following:
if (1==1)
if (1 + 1 == 2)
The following 'works'
int x = 1;
if (2 * x == 2)
throw...
What expression is obviously true to a human yet not to the compiler? The best I could manage was
bool False =>false;
if (False)
...and it has the wonderful property that to switch it off all I have to do is change it to
bool False=>true /* :D) */
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