good way to see which condition is met in python

I have three different if conditions and want to see which conditions are met.

I thought I could work this with an empty list and append 1 if the condition is met and 0 otherwise.

check_list = []
sample = [1,4,7]
fixed_number = 5

if sample[0] < fixed_number:
    check_list.append(1)
else:
    check_list.append(0)

if sample[1] < fixed_number:
    check_list.append(1)
else:
    check_list.append(0)

if sample[2] < fixed_number:
    check_list.append(1)
else:
    check_list.append(0)


check_list

desired output in this case:

[1,1,0]

How can I make this code short and pythonic?

thank you.