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- How do I compare strings in Java? 23 answers
I have 2 class files. The code of both classes are given below. I run the program and give the values aaa 15 mumbai bbb 15 mumbai ccc 15 mumbai
I expect the output to be 3, but it gives 0.
Student.java
public class Student{
public String name;
public double age;
public String city;
public Student(String a,Double b,String c){
this.name=a;
this.age=b;
this.city=c;
}
}
Solution.java
import java.util.Scanner;
public class Solution{
public static int studentCountWithSameCityAndAge(Student x,Student y,Student z){
int count=0;
if((x.age==y.age)&&(x.city==y.city)){
count=2;
}
if((x.age==z.age)&&(x.city==z.city)){
count++;
}
else if((x.age==z.age)&&(x.city==z.city)){
count=2;
}
else if((y.age==z.age)&&(y.city==z.city)) {
count=2;
}
return count;
}
public static void main(String args[]){
Scanner scan=new Scanner(System.in);
String name,city;
double age;
Student e1,e2,e3;
name=scan.nextLine();
age=scan.nextDouble();
scan.nextLine();
city=scan.nextLine();
e1=new Student(name,age,city);
System.out.println(e1.name+" "+e1.age+" "+e1.city);
name=scan.nextLine();
age=scan.nextDouble();
scan.nextLine();
city=scan.nextLine();
e2=new Student(name,age,city);
System.out.println(e2.name+" "+e2.age+" "+e2.city);
name=scan.nextLine();
age=scan.nextDouble();
scan.nextLine();
city=scan.nextLine();
e3=new Student(name,age,city);
System.out.println(e3.name+" "+e3.age+" "+e3.city);
int num;
num=studentCountWithSameCityAndAge(e1,e2,e3);
System.out.println(num);
}
}
I expect the output to be 3, but it gives 0.
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