I'm currently practicing Haskell in a number of ways. using lists to create a ton of fun things. Now I'm (think) having problems with understanding if statements.
What I want to do is make a Focuslist that shifts the focus to the most left item. Focuslists are already quite tricky, essentially being two independent lists. And it also splits the whole list in half, and reverses the back list.
For instance. If you want to make a focuslist of [0,1,2,3,4,5], and want a focus on 3, The focuslist will be [3,4,5][2,1,0].
I've already made three specific functions. One that makes the focuslist datatype:
data FocusList a = FocusList { forward :: [a], backward :: [a]}
With which you can call it by using
fromList :: [a] -> FocusList a
fromList list = FocusList list []
One that changes it back to a list from a focuslist:
toList :: FocusList a -> [a]
toList (FocusList fw bw) = reverse bw ++ fw
and one that shifts it to left once, changes [0,1,2,3,4,5] to [0,1,2,3,4,5] which now looks like [2,3,4,5][0,1] as focuslist:
goLeft :: FocusList a -> FocusList a
goLeft (FocusList fw (f:bw)) = FocusList (f:fw) bw
Now, to the main point. If I were to shift it all the way to the left. I want to use goLeft until the length of the list is 1. I was thinking of using a recursive if statement until the length of the first list equals to one. and using goLeft if it was not one.
So i thought of a simple if statement. Which (for now) doesn't work at all. it uses leftMost :: FocusList a -> FocusList a
leftMost (FocusList fw (f:bw)) = if (length (FocusList fw) == 1)
then FocusList (f:fw) bw
return leftMost
else FocusList fw (f:bw)
I was thinking of it the pythonic way. Which doesn't seem to work. How do I make it logically recursive?
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