Switch Case In ActionPerformed?

Ive gone through some stack overflow questions and found this similar question.

From what I understand using a switch statement in an actionPerformed method for this context will not work and an if-else statement is required.

Is there a more efficient way to do this without having repetitive code? I've heard I could use Abstract Action to give multiple buttons the same action but i haven't figured out how to use it properly.

@Override
    public void actionPerformed(ActionEvent e) {
        if(e.getSource() == loginButton){
            cardLayout.show(cards, LOGIN_PANEL);
        }
        else if(e.getSource() == signUpButton){
            cardLayout.show(cards, SIGN_UP_PANEL);
        }
        else if(e.getSource() == transactionHistoryButton){
            cardLayout.show(cards,TABLE_PANEL);
        }
        else if(e.getSource() == depositButton){
            cardLayout.show(cards, DEPOSIT_PANEL);
        }
        else if(e.getSource() == withdrawButton){
            cardLayout.show(cards, WITHDRAW_PANEL);
        }
        else if(e.getSource() == checkBalanceButton){
            cardLayout.show(cards,BALANCE_PANEL);
        }
        else if(e.getSource() == logout){
            cardLayout.show(cards, OPTION_PANEL);
        }
        else if(e.getSource() == backButtonP1){
            cardLayout.show(cards, OPTION_PANEL);
        }
        else if(e.getSource() == backButtonP2){
            cardLayout.show(cards, OPTION_PANEL);
        }
        else if(e.getSource() == backButtonP3){
            cardLayout.show(cards, UNLOCKED_PANEL);
        }
        else if(e.getSource() == backButtonP4){
            cardLayout.show(cards, UNLOCKED_PANEL);
        }
        else if(e.getSource() == backButtonP5){
            cardLayout.show(cards, UNLOCKED_PANEL);
        }
        else if(e.getSource() == backButtonP6){
            cardLayout.show(cards, UNLOCKED_PANEL);
        }
    }