mercredi 3 novembre 2021

How to make an if statement to check if all three items in list is present in another list

This is a bare sample of what I'm trying to build and I don't know why the combination of "wallet" and "ring" can pass as win.

I want the player to obtain all three items in order to win. Do you pose better solution to this?

import sys
inventory = []
def addtoInventory(item):
    inventory.append(item)

def room():
    print('you are in a living room, you say a card. Pick it up?')
    pickup = input()
    while pickup:
        if pickup == 'yes':
            addtoInventory("card")
            secondroom()
        else:
            print("you didnt pick it up")
            secondroom()
def secondroom():
    print('you are now in bedroom, theres a wallet, pick it up?')
    pickup = input()
    while pickup:
        if pickup == 'yes':
            addtoInventory("wallet")
            bathroom()
        else:
            print("you didnt pick it up")
            bathroom()
def bathroom():
    print('you are now in bathroom, theres a ring, pick it up?')
    pickup = input()
    while pickup:
        if pickup == 'yes':
            addtoInventory('ring')
            mall()
        else:
            print("you didnt pick it up")
            mall()
 
def mall():
    endgame = ["wallet", "card", "ring"]
    print('you are about to get a taxi to the pawn shop. do you have everything you need?')
    answer = input()
    print(inventory)
    while answer:
        if answer == 'yes':
            for item in endgame:
                if item not in inventory:
                    print("you lose")
                    sys.exit()
                else:
                    print("you won")
                    sys.exit()
            else:
                print("you lose")
                break

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