C programming error if statement

i have this program and it's working fine until the very end. When I ask the user if he/she wants to do a discount and the user enters y/n, the program just halts and doesn't go to the if statement. Any help? Thanks

#include <stdio.h>

int c;
int code;
int quantity;
double amount;
double total=0;
int i;
char ask;
double discount;
double disc;
double net;
int anykey;
double prices[7]= { 2.55, 12.07, 2.00, 0.55, 5.35, 8.65, 2.55};

int main(void)
{
    menu();
}


int menu()
{
    printf("1.Create a new bill\n");
    printf("2.Exit\n");
    scanf("%d",&c);
    switch(c){
    case 1: function();
        break;
    case 2: return 0;
        break;
}

return 0;
}

int function()

{   do{
    printf("Enter the code: ");
    scanf("%d",&code);

    if(code != -1){
        printf("Enter quantity: ");
        scanf("%d",&quantity);
        amount= ((prices[code]) * quantity);
        total= (total + amount);
        //printf("%.2f\n",total); for me to check
        }

    } while (code !=-1);
    calculate();
    getchar();

    return 0;

}

int calculate(){

printf("Do you want to make a discount? y/n \n");
scanf("%c",&ask);

if (ask == 'y')
{
    printf("Enter the actual money that you want to make a discount\n");
    scanf("%f",&disc);
    discount= (total * (disc/100));
    net= (total - discount);
    printf("The total bill is: %.2f\n", net);


}
else
if(ask == 'n')
{
        printf("The total bill is: %.2f\n", total);


    }
//menu();
return 0;

}