Create Python List using a True/False expression check?

Looking to generate a Python list that uses an if statement to check whether a number is even or odd. If even take the List value as '1' and if odd take the list value as '0'.

Progress to date:

List1 = [x for x in range(0,99) if x % 2 == 0]

However, this only generates a list of even numbers. When I change the expression to add an else check I get a syntax error. Any help appreciated.

List1 = [1 for x in range(0,99) if x % 2 == 0 else 0]