checking a flot number in python3.x [duplicate]

This question already has an answer here:

• Is floating point math broken? 28 answers
• What is the best way to compare floats for almost-equality in Python? 10 answers

Please someone can help me. I'm trying to inc the var t and when t == 3.14 I want to restart this loop setting t = 0.

The "print(t)" thing is an attempt to debug my code

Can someone, please, explain me what's happening here? Thanks!

Here's the code:

import time

t = 0
while 1:
    t += 0.10
    print(t)
    time.sleep(0.5)
    if t == 3.14:
        t = 0

Here's what's happening:

0.1

0.2

0.30000000000000004

0.4

0.5

0.6

0.7

0.7999999999999999

0.8999999999999999

0.9999999999999999

1.0999999999999999

1.2

1.3

1.4000000000000001

1.5000000000000002

1.6000000000000003

1.7000000000000004

1.8000000000000005

1.9000000000000006

2.0000000000000004

2.1000000000000005

2.2000000000000006

2.3000000000000007

2.400000000000001

2.500000000000001

2.600000000000001

2.700000000000001

2.800000000000001

2.9000000000000012

3.0000000000000013

3.1000000000000014

3.2000000000000015

3.3000000000000016