I am using this method for fetching data from the database to show them as a single page but it's giving me a link look like this one http://ift.tt/2t36em8. How can I make like this link instead of my one http://ift.tt/2umG7dG ?
<?php
$page = $_GET['v']; /* Page ID*/
$sel_database ="";
if($page == 'gfx'){ $sel_database="SELECT * FROM table ORDER BY table_id DESC ";}
if($page == 'frontend'){ $sel_database="SELECT * FROM table1 ORDER BY table1_id DESC "; }
$qri_res = mysqli_query($con,$sel_database);
while($total_row=mysqli_fetch_array($qri_res)){ /** Data Fetching Start **/
?>
<div class="container">
<!--Gig start-->
<div class="single-program">
<div class="gig-title">
<h2>
<?php if($page == 'gfx'){?>
<a href="post.php?v=<?= $total_row['gfx_id']?>&post=1">
<?php echo $total_row['gfx_title'];?>
</a>
<?php }?>
<?php if($page == 'frontend'){?>
<a href="post.php?v=<?= $total_row['frontend_id']?>&post=2">
<?php echo $total_row['frontend_title'];?>
</a>
<?php }?>
</h2>
<div class=" pricing">
<?php
if($page == 'gfx'){echo $total_row['gfx_price'];}
if($page == 'frontend'){echo $total_row['frontend_price'];}
?>
</div>
</div>
</div>
</div>
<?php }?>
<!-- Data Fetching end -->
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