I'm trying to create an if loop containing two else if in r, however I I get the following error: "unexpected token else" screenshot of the error in r
for these two else if:
else if(x=="container10ft") else if(x=="container20ft")
This is the code:
nearest_hub <- name_closest(request_info$location[1])
second_nearest <- name_second(request_info$location[1])
third_nearest <- name_third(request_info$location[1])
fourth_nearest <- name_fourth(request_info$location[1])
x= "container10ft"
n= 1
con_name= request_info$location[1]
if(x == "trailer"){
if( (hubs[nearest_hub,5]+ n) <= 6 && (hubs[nearest_hub,4]+ n) <= 2 && (hubs[nearest_hub,3]+ n) <= 1){
hubs[nearest_hub,5] = hubs[nearest_hub,5] + n
#up to now it decreases the no. of space available but I do not know how to syncronize the duration of request and the time of booking
shipment_cost = 0
} else if( (hubs[second_nearest,5]+ n) <= 6 && (hubs[second_nearest,4]+ n) <= 2 && (hubs[second_nearest,3]+ n) <= 1) {
hubs[second_nearest,5] = hubs[second_nearest,5]+ n
shipment_cost <- shipment_nearest_2(con_name)*cost_trailer_shipment*n
} else if( (hubs[third_nearest,5]+ n) <= 6 && (hubs[third_nearest,4]+ n) <= 2 && (hubs[third_nearest,3]+ n) <= 1){
hubs[third_nearest,5] = hubs[third_nearest,5]+ n
shipment_cost <- shipment_nearest_3(con_name)*cost_trailer_shipment*n
} else if( (hubs[fourth_nearest,5]+ n) <= 6 && (hubs[fourth_nearest,4]+ n) <= 2 && (hubs[fourth_nearest,3]+ n) <= 1){
hubs[fourth_nearest,5] = hubs[fourth_nearest,5]+ n
shipment_cost <- shipment_nearest_3(con_name)*cost_trailer_shipment*n
}}
else if(x=="container10ft"){
if((hubs[nearest_hub,5] + n) <= 6 && (hubs[nearest_hub,4] + n) <= 2 && (hubs[nearest_hub,3] + n) <= 1){
hubs[nearest_hub,4] = hubs[nearest_hub,4] + n
#up to now it decreases the no. of space available but I do not know how to syncronize the duration of request and the time of booking
shipment_cost <-shipment_nearest(con_name)* cost_10ft_shipment
} else if((hubs[second_nearest,5] + n) <= 6 && (hubs[second_nearest,4] + n) <= 2 && (hubs[second_nearest,3] + n) <= 1) {
hubs[second_nearest,4] = hubs[second_nearest,4] + n
shipment_cost <- shipment_nearest_2(con_name)*cost_10ft_shipment
} else if((hubs[third_nearest,5] + n) <= 6 && (hubs[third_nearest,4]+ n) <= 2 && (hubs[third_nearest,3] + n) <= 1){
hubs[third_nearest,4] = hubs[third_nearest,4] + n
shipment_cost <- shipment_nearest_3(con_name)*cost_10ft_shipment
} else if((hubs[fourth_nearest,5] + n) <= 6 && (hubs[fourth_nearest,4] + n) <= 2 && (hubs[fourth_nearest,3] + n) <= 1){
hubs[fourth_nearest,4] = hubs[fourth_nearest,4] + n
shipment_cost <- shipment_nearest_3(con_name)*cost_10ft_shipment
}
}
else if(x=="container20ft"){
if((hubs[nearest_hub,5] + n) <= 6 && (hubs[nearest_hub,4] + n) <= 2 && (hubs[nearest_hub,3] + n) <= 1){
hubs[nearest_hub,3] = hubs[nearest_hub,3]+ n
#up to now it decreases the no. of space available but I do not know how to syncronize the duration of request and the time of booking
shipment_cost <- shipment_nearest(con_name)*cost_20ft_shipment
} else if((hubs[second_nearest,5] + n) <= 6 && (hubs[second_nearest,4] + n) <= 2 && (hubs[second_nearest,3] + n) <= 1) {
hubs[second_nearest,3] = hubs[second_nearest,3] + n
shipment_cost <- shipment_nearest_2(con_name)*cost_20ft_shipment
} else if((hubs[third_nearest,5] + n) <= 6 && (hubs[third_nearest,4] + n) <= 2 && (hubs[third_nearest,3] + n) <= 1){
hubs[third_nearest,3] = hubs[third_nearest,3] + n
shipment_cost <- shipment_nearest_3(con_name)*cost_20ft_shipment
} else if((hubs[fourth_nearest,5] + n) <= 6 && (hubs[fourth_nearest,4]+ n) <= 2 && (hubs[fourth_nearest,3] + n) <= 1){
hubs[fourth_nearest,3] = hubs[fourth_nearest,3] + n
shipment_cost <- shipment_nearest_3(con_name)* cost_20ft_shipment }}
` Therefore, whenever I try tu run the code, R just runs the first if statement and then it stops. It seems r does not recognize that x could have three different options ( trailer, container10ft and container20ft). Thank you in advance
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